Tehtävä tunnilta, taittumissiirto.
AO=2.5
OAC=55
cos(OAC)=OA/AC
cos(55)=2.5/AC
AC*cos(55)=2.5
AC=2.5/cos(55)
AC=4.358616989052744
sin(b)/sin(a)=1/1.5
a=55
sin(b)/sin(55)=1/1.5
b=33.09995908918575
cos(b)=OA/AB
AB*cos(b)=2.5/AC
AB=2.5/cos(b)
AB=2.984293876605293
OC=sqrt(AC^2-OA^2)
OC=sqrt(4.358616989052744^2-2.5^2)=3.570370016855285
OB=sqrt(AB^2-OA^2)
OB=sqrt(2.984293876605293^2-2.5^2)=1.629726953186897
BC=OC-OB=1.940643063668388≈1.94cm